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5b^2-11b-1b-2=0
We add all the numbers together, and all the variables
5b^2-12b-2=0
a = 5; b = -12; c = -2;
Δ = b2-4ac
Δ = -122-4·5·(-2)
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{46}}{2*5}=\frac{12-2\sqrt{46}}{10} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{46}}{2*5}=\frac{12+2\sqrt{46}}{10} $
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